15x^2-19x+4=0

Solution for 15x^2-19x+4=0 equation:

Simplifying
15x2 + -19x + 4 = 0

Reorder the terms:
4 + -19x + 15x2 = 0

Solving
4 + -19x + 15x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(4 + -15x)(1 + -1x) = 0

Subproblem 1
Set the factor '(4 + -15x)' equal to zero and attempt to solve:

Simplifying
4 + -15x = 0

Solving
4 + -15x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -15x = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -15x = 0 + -4
-15x = 0 + -4

Combine like terms: 0 + -4 = -4
-15x = -4

Divide each side by '-15'.
x = 0.2666666667

Simplifying
x = 0.2666666667
Subproblem 2
Set the factor '(1 + -1x)' equal to zero and attempt to solve:

Simplifying
1 + -1x = 0

Solving
1 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1x = 0 + -1
-1x = 0 + -1

Combine like terms: 0 + -1 = -1
-1x = -1

Divide each side by '-1'.
x = 1

Simplifying
x = 1
Solution
x = {0.2666666667, 1}